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| From: | Joseph <syscon780@×××××.com> | ||
|---|---|---|---|
| To: | gentoo-user@l.g.o | ||
| Subject: | Re: [gentoo-user] search and replace "carriage return" | ||
| Date: | Tue, 04 Feb 2014 00:06:23 | ||
| Message-Id: | 20140204000638.GC6850@syscon7.ed.shawcable.net | ||
| In Reply to: | Re: [gentoo-user] search and replace "carriage return" by Mike Gilbert |
||
| 1 | On 02/03/14 18:52, Mike Gilbert wrote: |
| 2 | >On Mon, Feb 3, 2014 at 6:14 PM, Joseph <syscon780@×××××.com> wrote: |
| 3 | >> I have a text file. How do I search and replace "carriage return"? |
| 4 | >> |
| 5 | > |
| 6 | >Do you mean carriage return (decimal 13) or line feed (decimal 10)? |
| 7 | > |
| 8 | >The former is pretty simple: |
| 9 | > |
| 10 | >sed -e 's:\r: :g' foo.txt |
| 11 | |
| 12 | I've found this worked for me: |
| 13 | cat 16.txt | tr '\n' ' ' > 18.txt |
| 14 | |
| 15 | -- |
| 16 | Joseph |