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On Mon, Jul 19, 2004 at 06:33:49PM +0100, Tom Knight wrote: |
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> |
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> The solution is to do it like this: |
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> |
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> [ `use foo` ] && bar |
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> |
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> Which returns true if foo is in USE, but doesn't output the USE flag. |
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OK, have had a word with a few people on #g-dev, the way that the use |
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function works is going to change so that it doesn't output the use flag, so |
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ignore what I said in the last message. |
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tom |
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-- |
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Tom Knight |
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tomk@g.o |
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GPG Public Key: http://dev.gentoo.org/~tomk/tomk.asc |