[gentoo-user] Help With Cron

[Drew Tomlinson]

My cron program is sys-process/vixie-cron-4.1-r9 and all cron jobs but 
one are running as I expect.  Specifically, I want the following command 
to execute from cron:

/usr/share/mythtv/mythrename.pl --format "%T %- %Y-%m-%d_%g-%i %A %- %S" 
--link /tv/pretty

However it fails to run and I get this error message emailed to me from 
cron:

From: mythtv@×××××××××××××××××.net
Date: Tue, 10 Apr 2007 15:07:01 -0700
To: drew@××××××××××××××.net
Subject: Cron <mythtv@tv> /usr/share/mythtv/mythrename.pl --format "
X-Cron-Env: <MAILTO=drew@××××××××××××××.net>
X-Cron-Env: <SHELL=/bin/sh>
X-Cron-Env: <HOME=/home/mythtv>
X-Cron-Env: <PATH=/usr/bin:/bin>
X-Cron-Env: <LOGNAME=mythtv>
X-Cron-Env: <USER=mythtv>
Message-Id: <20070410220701.655A716495E@××××××××××××××××××××××××.net>

/bin/sh: -c: line 0: unexpected EOF while looking for matching `"'
/bin/sh: -c: line 1: syntax error: unexpected end of file

So I suspected the quotes in my command line might be the problem and I 
removed the '--format " ..."' part.  Thus my command looked like this:

/usr/share/mythtv/mythrename.pl --link /tv/pretty

But still I received email with the same error.

I don't understand what cron doesn't like.  The command runs just fine 
as the user from the command line.  Can someone please point me in the 
right direction?

Thanks,

Drew

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