From: | Ow Mun Heng <Ow.Mun.Heng@×××.com> |
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To: | gentoo-user@l.g.o |
Subject: | [gentoo-user] Escaping a "*" in bash script |
Date: | Sun, 08 Oct 2006 10:19:46 |
Message-Id: | 1160302437.15995.27.camel@neuromancer.home.net |
1 | Does anyone know how to go about escaping a "*" in a bash script? |
2 | |
3 | I want to do the following |
4 | |
5 | query=" select * from table where column1='something' " |
6 | |
7 | |
8 | |
9 | -- |
10 | gentoo-user@g.o mailing list |
Subject | Author |
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Re: [gentoo-user] Escaping a "*" in bash script | Daniel Waeber <_wabu@×××.de> |
Re: [gentoo-user] Escaping a "*" in bash script [SOLVED] | Ow Mun Heng <Ow.Mun.Heng@×××.com> |
Re: [gentoo-user] Escaping a "*" in bash script | Mark <znxster@×××××.com> |