Re: [gentoo-user] search and replace "carriage return"

[Joseph]

On 02/03/14 18:52, Mike Gilbert wrote:
>On Mon, Feb 3, 2014 at 6:14 PM, Joseph <syscon780@×××××.com> wrote:
>> I have a text file.  How do I search and replace "carriage return"?
>>
>
>Do you mean carriage return (decimal 13) or line feed (decimal 10)?
>
>The former is pretty simple:
>
>sed -e 's:\r: :g' foo.txt

OK here is the text output (last few lines) of the command: cat 15.txt | sed 's/\r$//' | od -c

...
0017460   o   w       t   h   e       m   a   j   o   r       g   r   o
0017500   u   p   i   n   g   s       o   f  \n   d   i   n   o   s   a
0017520   u   r   s   .  \n   L   e   t   '   s       m   o   v   e    
0017540   o   n       f   r   o   m       d   i   n   o   s   a   u   r
0017560       s   k   e   l   e   t   o   n   s       t   o  \n   o   u
0017600   t   w   a   r   d       a   p   p   e   a   r   a   n   c   e
0017620   s   .  \n

the actual text:
ow the major groupings of
dinosaurs.
Let's move on from dinosaur skeletons to
outward appearances.

so it seems to me the carriage return is represented by: " \n"

I've tried 
sed -e 's:\n: :g' 15.txt

makes no difference. How to replace the "\n" with space.

-- 
Joseph