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On Saturday 24 May 2008, Andrey Falko wrote: |
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> On Sat, May 24, 2008 at 11:32 AM, Andrey Falko <ma3oxuct@×××××.com> wrote: |
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> > On Sat, May 24, 2008 at 11:22 AM, Robin Atwood |
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> > |
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> > <robin.atwood@×××××××××.net> wrote: |
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> >> Regexs are not my strong point! I am trying to get a list of service |
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> >> scripts that provide virtual services. Each such script contains a line |
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> >> like: |
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> >> |
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> >> provide dns |
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> >> |
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> >> i.e. the line starts with one or more spaces, followed by the text |
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> >> "provide", followed by one or more spaces and a single word. i have come |
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> >> up with: |
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> >> |
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> >> grep -e ^\s+provide\s+\w /etc/init.d |
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> > |
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> > Right now you are saying: match one or more spaces in the begining |
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> > followed by provide followed by one or more spaces followed by *one* |
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> > word followed by one space and followed by /etc/init.d |
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> > |
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> > I think you mean: grep -e ^\s+provide\s+\w+ /etc/init.d |
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> > |
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> >> but, as usual, nothing is matched. What am I doing wrong? |
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> |
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> I see your mistake....\w means alphanumeric character, not word. |
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I had just realised that myself. However, it still doesn't work. :( |
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Thanks for trying, though. |
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-Robin |
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