From: | Adam Carter <adamcarter3@×××××.com> |
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To: | "gentoo-user@l.g.o" <gentoo-user@l.g.o> |
Subject: | [gentoo-user] bash script question |
Date: | Mon, 18 Aug 2014 08:55:03 |
Message-Id: | CAC=wYCHQMa77RxBpFYs878T7j61PiMWZUWoXLjc2QnwpU794DA@mail.gmail.com |
1 | I want to use an if/then that tests for the existence of a string in 4 |
2 | files. Usually I do this by checking the exit code of grep, when i'm |
3 | checking a single file. However, I cant get the syntax right for multiple |
4 | checks. |
5 | |
6 | |
7 | |
8 | To troubleshoot I’ve dropped back to just checking two files, and i’ve |
9 | tried things like |
10 | |
11 | |
12 | |
13 | If [ $(grep blah file1.txt) –a $(grep blah file2.txt) ]; then |
14 | |
15 | |
16 | |
17 | But this matches if grep fails both times as well as when it matches both |
18 | time. Any ideas? |
Subject | Author |
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Re: [gentoo-user] bash script question | wraeth <wraeth@×××××××××.au> |