| 1 |
On Sun, 2006-10-08 at 18:13 +0800, Ow Mun Heng wrote: |
| 2 |
> Does anyone know how to go about escaping a "*" in a bash script? |
| 3 |
> |
| 4 |
> I want to do the following |
| 5 |
> |
| 6 |
> query=" select * from table where column1='something' " |
| 7 |
> |
| 8 |
|
| 9 |
nevermind.. |
| 10 |
|
| 11 |
I did it like this |
| 12 |
query=" select \" *\" from table where column1='something' " |
| 13 |
|
| 14 |
and though it echoes back as |
| 15 |
select "*" from.... |
| 16 |
|
| 17 |
when it gets to the SQL server, it's actually |
| 18 |
select * from .... |
| 19 |
|
| 20 |
|
| 21 |
oh well.. |
| 22 |
-- |
| 23 |
gentoo-user@g.o mailing list |
Archives