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On Sun, 4 Mar 2012 13:56:23 -0800 |
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Grant <emailgrant@×××××.com> wrote: |
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|
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> >> [snip] |
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> >>>> 1. fdisk won't let me specify a start block before 2048 even |
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> >>>> though I deleted all partitions. |
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> >>>> |
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> >>> |
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> >>> That's normal. It's a long story, but Windows Vista and Windows 7 |
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> >>> expects the first partition to start at sector 2048. |
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> >>> |
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> >>> You can force a lower number by toggling "DOS compatibility"; |
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> >>> this should let you start the first partition as low as sector 63. |
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> >>> |
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> >>> HOWEVER, make sure that all partitions begin at multiples of 8 |
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> >>> (e.g., 64, 72, 80, and so on); this will save you a lot of grief |
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> >>> if it happens that the hard disk you're using has 4KiB-sectors. |
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> >> |
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> >> I just looked up the start block for my other systems and they're |
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> >> all on 63. Is performance impacted on all of these systems since |
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> >> they aren't started on 64? |
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> >> |
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> >> - Grant |
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> >> |
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> > |
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> > The performance is only impacted if the sector size is something |
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> > other than 512 bytes. The newer 4K sector size used by some higher |
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> > density drives requires that you start partitions on a sector |
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> > boundary or they will perform badly. There isn't an actually |
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> > performance need to actually start on 2048 but the fdisk-type |
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> > developer folks are doing that to be more compatible with newer |
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> > Windows installations. |
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> |
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> All my drives says this from fdisk: |
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> |
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> Units = sectors of 1 * 512 = 512 bytes |
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> Sector size (logical/physical): 512 bytes / 512 bytes |
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> I/O size (minimum/optimal): 512 bytes / 512 bytes |
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> |
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> So it doesn't matter where the first partition starts? |
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|
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Correct. Those drives are all the same style as you've |
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been using for years. If partitions start at 63, that's just an msdos |
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convention. For reasons I've never understood, Windows liked to reserve |
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the first 32k for some purpose or other. |
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|
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|
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-- |
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Alan McKinnnon |
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alan.mckinnon@×××××.com |