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Le 23/01/2019 à 04:19, Adam Carter a écrit : |
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> > François-Xavier |
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> > |
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> > |
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> |
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> My bad, it should be: |
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> |
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> sed 's/0*\([0-9][0-9]*\)/\1/g' |
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> |
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> (tests are indeed needed!) |
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> |
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> |
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> Many thanks François. This is almost right, but it is also stripping |
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> zeros that follow a letter, and I only want it to strip zeros that are |
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> proceeded by a period. There are no leading zeros in the first octet of |
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> the IP so that case does not need to be handled. |
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> |
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> Does the \1 refer to what's in the ()'s? So anything that one would wont |
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> to carry through should be inside the ()'s and anything that's outside |
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> is stripped, right? |
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> |
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> |
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> |
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Yes, \1 is the content in (). But adding letters inside won't solve the |
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problem, eg. "a01" will still be changed to "a1". |
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AFAIK, there is no way to express "start of line or a character" in sed, |
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but you could do two regexps, one starting with ^ (start of line), the |
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other with \. (dot) |
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sed 's/^0*\([0-9][0-9]*\)/\1/g;s/\.0*\([0-9][0-9]*\)/.\1/g' |
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