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On 11/08/15 06:10 AM, Sergey Popov wrote: |
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> Err, i have read the whole thread and still does not get a point, |
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> why i am wrong. |
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> |
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> It's old battle like we have beforce with "gtk" meaning "any |
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> versions of GTK flag". This behaviour should be killed with fire. |
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> |
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> Let's me reiterate some of the cases: |
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> |
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> 1. Package can be build without Qt GUI at all, but either Qt4 or |
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> Qt5 can be chosen, but not both. |
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> |
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> Fix this with REQUIRED_USE, do not enable any of Qt flags by |
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> default |
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> |
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Why does this need REQUIRED_USE at all? neither flag is necessary, |
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and just because the package only uses one flag at a time doesn't mean |
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we should require users that have both flags set in profiles to -have |
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to- package.use one of them off. |
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> 2. Package can not be build without Qt GUI - either Qt4 or Qt5 is |
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> required, but not both |
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> |
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> Same thing here, different REQUIRED_USE operator. But - enable one |
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> of the flags by default to ease life of users. |
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> |
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IUSE="qt4 +qt5" and USE="qt4 -qt5" globally (ie from profiles) is |
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going to make a REQUIRED_USE force an exception in package.use as |
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well. Again, annoying to end-users for no overly good reason and see #1 |
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. |
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> 3. Package can be build with Qt4 or Qt5 or both AT THE SAME TIME(if |
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> such package even exists?) |
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> |
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> Do not use REQUIRED_USE here, not needed. |
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> |
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> Now, please tell me, where am i wrong? |
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> |
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IMO it's wrong because REQUIRED_USE is a BFH for what really ends up |
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as an extra, dangling enabled use flag. Unless there's a case (and i |
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truely doubt there is) that there's a package with IUSE="qt4" that |
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depends on ANOTHER package with IUSE="qt4 qt5", and that other package |
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only builds against one implementation, AND the dep on the first |
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package doesn't include any use deps, I still see no actual -need- for |
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REQUIRED_USE. |
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