1 |
On Sat, 29 Sep 2012 19:38:50 -0400 |
2 |
Rich Freeman <rich0@g.o> wrote: |
3 |
|
4 |
> On Sat, Sep 29, 2012 at 5:21 PM, Ulrich Mueller <ulm@g.o> |
5 |
> wrote: |
6 |
> The license isn't binary-only. The license is BSD. It just happens |
7 |
> that the thing they're licensing is the binary and not the source. |
8 |
> |
9 |
> Does it really matter? Before we start overloading the LICENSE flag |
10 |
> to represent something other than the license we should probably have |
11 |
> a problem to actually fix. |
12 |
> |
13 |
> As far as freedom of code goes, arguably the code is perfectly free - |
14 |
> it just isn't open source. You could legally decompile, modify, |
15 |
> recompile, and redistribute it and your assembly language sources as |
16 |
> much as you like. |
17 |
|
18 |
Imho software as it's described here shouldn't get a LICENSE which is |
19 |
in @FREE, such as BSD. |
20 |
|
21 |
For a software to be free, it has to be possible to change it in any |
22 |
way you want. And "to be possible" and "to be allowed" really aren't |
23 |
the same here! (Except if you are either masochistic or one of these |
24 |
gurus which eat assembly code for breakfast). |
25 |
|
26 |
I have an ACCEPT_LICENSE="-* @FREE" in my make.conf, so I expect that |
27 |
there's only free software on my system (except for those packages I |
28 |
explicitly allowed via package.license, for sure). I couldn't make this |
29 |
assumption anymore if software as you describe it would get a @FREE |
30 |
LICENSE. |
31 |
|
32 |
Cheers, |
33 |
aranea |