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On Wed, Jan 27, 2016 at 04:28:43PM -0400, David M. Fellows wrote: |
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> On Wed, 27 Jan 2016 17:25:37 +0100 |
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> Meino.Cramer@×××.de wrote - |
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> > Hi, |
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> > |
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> > I want to determine the size of the contents of all directories of a |
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> > tree of directories on a hexacore AMD64 machine with 4GB RAM an one |
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> > harddisk (containing that tree) -- most efficiently (least time |
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> > consuming). |
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> > |
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> > I tried this (cwd = root of that tree): |
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> > |
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> > find . -depth -type d -print0 | xargs -0 -P 6 du -bsx {} \; |
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> > |
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> > . Is there any to do this faster? |
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> > |
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> > Thank you very much in advance for any help! |
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> > Best regards, |
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> > Meino |
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> |
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> man du |
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> |
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> Dave F |
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|
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|
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Here's a couple of nice ones: |
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< du -sh /* | sort -rh > |
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< du -axk / | awk '$1 > 2^20 {print}' | sort -rn | head -20 > |
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|
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You could also check out the application ncdu for a curses-based |
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du command analyzer. |
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