From: | wraeth <wraeth@×××××××××.au> | ||
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To: | gentoo-user@l.g.o | ||
Subject: | Re: [gentoo-user] bash script question | ||
Date: | Mon, 18 Aug 2014 09:43:15 | ||
Message-Id: | 1408354973.1863.1.camel@wraeth.id.au | ||
In Reply to: | [gentoo-user] bash script question by Adam Carter |
1 | On Mon, 2014-08-18 at 18:54 +1000, Adam Carter wrote: |
2 | > But this matches if grep fails both times as well as when it matches both |
3 | > time. Any ideas? |
4 | |
5 | If you don't mind using a quick loop, you could use something like: |
6 | |
7 | n=0 |
8 | for f in file1.txt file2.txt file3.txt file4.txt; do |
9 | grep 'string' ${f} >> /dev/null && n=$[n+1] |
10 | done |
11 | |
12 | if [[ $n == 4 ]]; then |
13 | do_something |
14 | fi |
15 | |
16 | |
17 | -- |
18 | wraeth <wraeth@×××××××××.au> |
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Re: [gentoo-user] bash script question | Stroller <stroller@××××××××××××××××××.uk> |