| 1 |
On Sat, Dec 20, 2008 at 08:35:47PM -0800, Penguin Lover Grant squawked: |
| 2 |
> Can I change the amount reserved for root? |
| 3 |
|
| 4 |
for ext2/3, try 'man tune2fs'. |
| 5 |
|
| 6 |
W |
| 7 |
|
| 8 |
-- |
| 9 |
Proof by contradiction: |
| 10 |
Suppose the square root of 3 were rational. Then sqrt(3) = p / q, for some |
| 11 |
relatively prime integers p and q. Hence p = q sqrt(3). Now, since the square |
| 12 |
root of 3 is irrational, p and q cannot both be rational and hence cannot both |
| 13 |
be integers, which contradicts the original supposition. Hence, sqrt(3) is |
| 14 |
irrational. |
| 15 |
~Daniel Jonathan Peng |
| 16 |
Pzzzt... DJP is just as irrational as the square root of three. |
| 17 |
Sortir en Pantoufles: up 744 days, 3:47 |
Archives