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On Wed, Jan 23, 2019 at 9:05 AM Paul Colquhoun |
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<paulcol@×××××××××××××××××.au> wrote: |
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> |
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> On Wednesday, 23 January 2019 5:52:57 PM AEDT Alexander Kapshuk wrote: |
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> > On Wed, Jan 23, 2019 at 5:20 AM Adam Carter <adamcarter3@×××××.com> wrote: |
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> > >> > François-Xavier |
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> > >> |
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> > >> My bad, it should be: |
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> > >> |
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> > >> sed 's/0*\([0-9][0-9]*\)/\1/g' |
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> > >> |
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> > >> (tests are indeed needed!) |
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> > > |
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> > > Many thanks François. This is almost right, but it is also stripping zeros |
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> > > that follow a letter, and I only want it to strip zeros that are |
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> > > proceeded by a period. There are no leading zeros in the first octet of |
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> > > the IP so that case does not need to be handled. |
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> > > |
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> > > Does the \1 refer to what's in the ()'s? So anything that one would wont |
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> > > to carry through should be inside the ()'s and anything that's outside is |
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> > > stripped, right? |
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> > Would something like to do the trick? |
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> > echo 198.088.062.01 | sed 's/\.0/./g' |
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> > 198.88.62.1 |
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> |
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> In a word, no. |
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> |
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> echo 198.088.0.01 | sed 's/\.0/./g' |
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> 198.88..1 |
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> |
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> |
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> -- |
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> Reverend Paul Colquhoun, ULC. http://andor.dropbear.id.au/ |
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> Asking for technical help in newsgroups? Read this first: |
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> http://catb.org/~esr/faqs/smart-questions.html#intro |
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> |
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> |
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> |
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> |
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|
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How about this one? |
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|
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echo '198.088.0.01 |
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198.088.062.01' | sed 's/\.0\([0-9][0-9]*\)/.\1/g' |
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198.88.0.1 |
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198.88.62.1 |
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