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On 23/01/19 07:37, Alexander Kapshuk wrote: |
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> On Wed, Jan 23, 2019 at 9:05 AM Paul Colquhoun |
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> <paulcol@×××××××××××××××××.au> wrote: |
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>> |
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>> On Wednesday, 23 January 2019 5:52:57 PM AEDT Alexander Kapshuk wrote: |
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>>> On Wed, Jan 23, 2019 at 5:20 AM Adam Carter <adamcarter3@×××××.com> wrote: |
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>>>>>> François-Xavier |
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>>>>> |
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>>>>> My bad, it should be: |
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>>>>> |
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>>>>> sed 's/0*\([0-9][0-9]*\)/\1/g' |
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>>>>> |
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>>>>> (tests are indeed needed!) |
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>>>> |
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>>>> Many thanks François. This is almost right, but it is also stripping zeros |
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>>>> that follow a letter, and I only want it to strip zeros that are |
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>>>> proceeded by a period. There are no leading zeros in the first octet of |
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>>>> the IP so that case does not need to be handled. |
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>>>> |
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>>>> Does the \1 refer to what's in the ()'s? So anything that one would wont |
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>>>> to carry through should be inside the ()'s and anything that's outside is |
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>>>> stripped, right? |
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>>> Would something like to do the trick? |
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>>> echo 198.088.062.01 | sed 's/\.0/./g' |
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>>> 198.88.62.1 |
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>> |
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>> In a word, no. |
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>> |
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>> echo 198.088.0.01 | sed 's/\.0/./g' |
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>> 198.88..1 |
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>> |
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>> |
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>> -- |
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>> Reverend Paul Colquhoun, ULC. http://andor.dropbear.id.au/ |
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>> Asking for technical help in newsgroups? Read this first: |
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>> http://catb.org/~esr/faqs/smart-questions.html#intro |
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>> |
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>> |
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>> |
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>> |
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> |
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> How about this one? |
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> |
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> echo '198.088.0.01 |
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> 198.088.062.01' | sed 's/\.0\([0-9][0-9]*\)/.\1/g' |
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> 198.88.0.1 |
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> 198.88.62.1 |
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> |
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|
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I've just done a bit of digging, and would this work to match an octet? |
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|
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[0-9][0-9]?[0-9]? |
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|
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I know ? normally matches a single character, but apparently in this |
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syntax it means "0 or 1 occurrence of the preceding expression". So that |
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will detect a number consisting of at most three digits. |
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|
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I thought there must be a "detect a single optional character" operator |
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... :-) |
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|
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Cheers, |
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Wol |
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