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Ow Mun Heng wrote: |
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> Does anyone know how to go about escaping a "*" in a bash script? |
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> |
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> I want to do the following |
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> |
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> query=" select * from table where column1='something' " |
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> |
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> |
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As you use the "" it is still a * in the $query, but you have to be |
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carefull when you use the variable. |
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Try something like dbcommand "$query" and it will still be a * in your |
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query |
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|
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- -- |
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wabu |
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